What are the solutions to the equation a^2+9a+18=0 ?

The solutions to the equation a^2+9a+18=0 are a=-3,a=-6

Find the zeros of a^2+9a+18=0

The zeros of a^2+9a+18=0 are a=-3,a=-6

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a^{2} + 9 a + 18 = 0

a = - 3, a = - 6

Solution steps

a^{2} + 9 a + 18 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 18 = 3

a_{1, 2} = \frac{- 9 \pm 3}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 9 + 3}{2 \cdot 1}, a_{2} = \frac{- 9 - 3}{2 \cdot 1}

a = \frac{- 9 + 3}{2 \cdot 1} : - 3

a = \frac{- 9 - 3}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

a = - 3, a = - 6

\frac{2}{x} > 4

p^{2} + 14 p + 13

4 r - 2 < 2

3 y^{2} - 17 y - 28

9 x^{2} + 24 x y + 16 y^{2}

What are the solutions to the equation a^2+9a+18=0 ?
The solutions to the equation a^2+9a+18=0 are a=-3,a=-6
Find the zeros of a^2+9a+18=0
The zeros of a^2+9a+18=0 are a=-3,a=-6