What are the solutions to the equation 4x^2=48 ?

The solutions to the equation 4x^2=48 are x=2sqrt(3),x=-2sqrt(3)

Find the zeros of 4x^2=48

The zeros of 4x^2=48 are x=2sqrt(3),x=-2sqrt(3)

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4 x^{2} = 48

x = 23, x = - 23

Decimal Notation

x = 3.46410 \dots, x = - 3.46410 \dots

Solution steps

4 x^{2} = 48

Divide both sides by

4

x^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 12, x = - 12

12 = 23

- 12 = - 23

x = 23, x = - 23

35 m^{2} + 31 m + 6

∣ x + 5 ∣ > 8

\frac{62.076}{800} \cdot 60

2 k^{2} - 5 k - 18

\frac{1}{2} \cdot 45

What are the solutions to the equation 4x^2=48 ?
The solutions to the equation 4x^2=48 are x=2sqrt(3),x=-2sqrt(3)
Find the zeros of 4x^2=48
The zeros of 4x^2=48 are x=2sqrt(3),x=-2sqrt(3)