What is (3m^4)/(3m+2)-(4m^2)/(5m+2) ?

The solution to (3m^4)/(3m+2)-(4m^2)/(5m+2) is (15m^5+6m^4-12m^3-8m^2)/((3m+2)(5m+2))

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simplify (3m^4)/(3m+2)-(4m^2)/(5m+2)

simplify

\frac{3 m ^{4}}{3 m + 2} - \frac{4 m ^{2}}{5 m + 2}

\frac{15 m ^{5} + 6 m ^{4} - 12 m ^{3} - 8 m ^{2}}{( 3 m + 2 ) ( 5 m + 2 )}

Solution steps

\frac{3 m ^{4}}{3 m + 2} - \frac{4 m ^{2}}{5 m + 2}

Least Common Multiplier of

3 m + 2, 5 m + 2 : (3 m + 2) (5 m + 2)

Adjust Fractions based on the LCM

= \frac{3 m ^{4} ( 5 m + 2 )}{( 3 m + 2 ) ( 5 m + 2 )} - \frac{4 m ^{2} ( 3 m + 2 )}{( 3 m + 2 ) ( 5 m + 2 )}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{3 m ^{4} ( 5 m + 2 ) - 4 m ^{2} ( 3 m + 2 )}{( 3 m + 2 ) ( 5 m + 2 )}

Simplify

3 m^{4} (5 m + 2) - 4 m^{2} (3 m + 2) : 15 m^{5} + 6 m^{4} - 12 m^{3} - 8 m^{2}

= \frac{15 m ^{5} + 6 m ^{4} - 12 m ^{3} - 8 m ^{2}}{( 3 m + 2 ) ( 5 m + 2 )}

(x - 4)^{2} = 0

- (\frac{1}{x})^{2}

∣ 3 + 2 x ∣ < ∣ 4 - x ∣

(\frac{8}{27})^{- \frac{4}{3}}

What is (3m^4)/(3m+2)-(4m^2)/(5m+2) ?
The solution to (3m^4)/(3m+2)-(4m^2)/(5m+2) is (15m^5+6m^4-12m^3-8m^2)/((3m+2)(5m+2))