What is (\frac{2x^7y)/(8x^9y^2)}{(x/(4y^2))^3} ?

The solution to (\frac{2x^7y)/(8x^9y^2)}{(x/(4y^2))^3} is (16y^5)/(x^5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (\frac{2x^7y)/(8x^9y^2)}{(x/(4y^2))^3}

simplify

\frac{\frac{2 x ^{7} y}{8 x ^{9} y ^{2}}}{( \frac{x}{4 y ^{2}} ) ^{3}}

\frac{16 y ^{5}}{x ^{5}}

Solution steps

\frac{\frac{2 x ^{7} y}{8 x ^{9} y ^{2}}}{( \frac{x}{4 y ^{2}} ) ^{3}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{2 x ^{7} y}{8 x ^{9} y ^{2} ( \frac{x}{4 y ^{2}} ) ^{3}}

Cancel

\frac{2 x ^{7} y}{8 x ^{9} y ^{2} ( \frac{x}{4 y ^{2}} ) ^{3}} : \frac{16 y ^{5}}{x ^{5}}

= \frac{16 y ^{5}}{x ^{5}}

\frac{x - 1}{x - 2} \geq x

3 u^{2} + 5 u - 8

10 a^{2} + 10 - 20

∣ 5 x - 3 ∣ = ∣ 3 x + 5 ∣

(\frac{4 mn}{m ^{- 2} n ^{6}})^{- 2}

What is (\frac{2x^7y)/(8x^9y^2)}{(x/(4y^2))^3} ?
The solution to (\frac{2x^7y)/(8x^9y^2)}{(x/(4y^2))^3} is (16y^5)/(x^5)