What are the solutions to the equation 1-0.2x-0.7x^2=0 ?

The solutions to the equation 1-0.2x-0.7x^2=0 are x=-(1+sqrt(71))/7 ,x=(sqrt(71)-1)/7

Find the zeros of 1-0.2x-0.7x^2=0

The zeros of 1-0.2x-0.7x^2=0 are x=-(1+sqrt(71))/7 ,x=(sqrt(71)-1)/7

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1 - 0.2 x - 0.7 x^{2} = 0

x = - \frac{1 + 71}{7}, x = \frac{71 - 1}{7}

Decimal Notation

x = - 1.34659 \dots, x = 1.06087 \dots

Solution steps

1 - 0.2 x - 0.7 x^{2} = 0

Multiply both sides by

10

10 - 2 x - 7 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 7 x^{2} - 2 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 7 ) \cdot 10}{2 ( - 7 )}

(- 2)^{2} - 4 (- 7) \cdot 10 = 271

x_{1, 2} = \frac{- ( - 2 ) \pm 2 71}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 71}{2 ( - 7 )}, x_{2} = \frac{- ( - 2 ) - 2 71}{2 ( - 7 )}

x = \frac{- ( - 2 ) + 2 71}{2 ( - 7 )} : - \frac{1 + 71}{7}

x = \frac{- ( - 2 ) - 2 71}{2 ( - 7 )} : \frac{71 - 1}{7}

The solutions to the quadratic equation are:

x = - \frac{1 + 71}{7}, x = \frac{71 - 1}{7}

x^{2} + 14 x = 15

5 x - 2 = - 12

551 - 13 j \geq 83

209

∣ x ∣ + 2 = 2 x

What are the solutions to the equation 1-0.2x-0.7x^2=0 ?
The solutions to the equation 1-0.2x-0.7x^2=0 are x=-(1+sqrt(71))/7 ,x=(sqrt(71)-1)/7
Find the zeros of 1-0.2x-0.7x^2=0
The zeros of 1-0.2x-0.7x^2=0 are x=-(1+sqrt(71))/7 ,x=(sqrt(71)-1)/7