What are the solutions to the equation 9x^2+17x+8=0 ?

The solutions to the equation 9x^2+17x+8=0 are x=-8/9 ,x=-1

Find the zeros of 9x^2+17x+8=0

The zeros of 9x^2+17x+8=0 are x=-8/9 ,x=-1

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9 x^{2} + 17 x + 8 = 0

x = - \frac{8}{9}, x = - 1

Solution steps

9 x^{2} + 17 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 9 \cdot 8}{2 \cdot 9}

1 7^{2} - 4 \cdot 9 \cdot 8 = 1

x_{1, 2} = \frac{- 17 \pm 1}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 17 + 1}{2 \cdot 9}, x_{2} = \frac{- 17 - 1}{2 \cdot 9}

x = \frac{- 17 + 1}{2 \cdot 9} : - \frac{8}{9}

x = \frac{- 17 - 1}{2 \cdot 9} : - 1

The solutions to the quadratic equation are:

x = - \frac{8}{9}, x = - 1

16 x^{2} - 8 x t - 3 t^{2}

x + 2 = 6 x - 18

- \frac{1}{2 ( 16 ) ^{\frac{3}{2}}}

\frac{x}{4} - 8 < 5

9 m + 14 = 2 m

What are the solutions to the equation 9x^2+17x+8=0 ?
The solutions to the equation 9x^2+17x+8=0 are x=-8/9 ,x=-1
Find the zeros of 9x^2+17x+8=0
The zeros of 9x^2+17x+8=0 are x=-8/9 ,x=-1