What are the solutions to the equation 2x^2+5x-50=0 ?

The solutions to the equation 2x^2+5x-50=0 are x=(-5+5sqrt(17))/4 ,x=(-5-5sqrt(17))/4

Find the zeros of 2x^2+5x-50=0

The zeros of 2x^2+5x-50=0 are x=(-5+5sqrt(17))/4 ,x=(-5-5sqrt(17))/4

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2 x^{2} + 5 x - 50 = 0

x = \frac{- 5 + 5 17}{4}, x = \frac{- 5 - 5 17}{4}

Decimal Notation

x = 3.90388 \dots, x = - 6.40388 \dots

Solution steps

2 x^{2} + 5 x - 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 50 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 50) = 517

x_{1, 2} = \frac{- 5 \pm 5 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 5 17}{2 \cdot 2}, x_{2} = \frac{- 5 - 5 17}{2 \cdot 2}

x = \frac{- 5 + 5 17}{2 \cdot 2} : \frac{- 5 + 5 17}{4}

x = \frac{- 5 - 5 17}{2 \cdot 2} : \frac{- 5 - 5 17}{4}

The solutions to the quadratic equation are:

x = \frac{- 5 + 5 17}{4}, x = \frac{- 5 - 5 17}{4}

\frac{- 320}{- 64}

∣ x - 1 ∣ + ∣ 4 - 2 x ∣ = 4

- \frac{1}{6} + \frac{3}{10}

3 s + 2 = 12 - 2 s

- 9 = c + (- 2) e^{- 8 (0)}

What are the solutions to the equation 2x^2+5x-50=0 ?
The solutions to the equation 2x^2+5x-50=0 are x=(-5+5sqrt(17))/4 ,x=(-5-5sqrt(17))/4
Find the zeros of 2x^2+5x-50=0
The zeros of 2x^2+5x-50=0 are x=(-5+5sqrt(17))/4 ,x=(-5-5sqrt(17))/4