What is (x^2+4x)/(x^2-36)<= 0 ?

The solution to (x^2+4x)/(x^2-36)<= 0 is -6<x<=-4\lor 0<= x<6

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(x^2+4x)/(x^2-36)<= 0

\frac{x ^{2} + 4 x}{x ^{2} - 36} \leq 0

- 6 < x \leq - 4 or 0 \leq x < 6

Interval Notation

(- 6, - 4] \cup [0, 6)

Solution steps

\frac{x ^{2} + 4 x}{x ^{2} - 36} \leq 0

Factor

\frac{x ^{2} + 4 x}{x ^{2} - 36} : \frac{x ( x + 4 )}{( x + 6 ) ( x - 6 )}

\frac{x ( x + 4 )}{( x + 6 ) ( x - 6 )} \leq 0

Identify the intervals

- 6 < x \leq - 4 or 0 \leq x < 6

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\frac{12}{52} \cdot \frac{4}{52}

46 x + 23 = 46 x + 23

7 - ∣ 2 x - 3 ∣ = 4

a^{8} - a^{2} b^{6}

What is (x^2+4x)/(x^2-36)<= 0 ?
The solution to (x^2+4x)/(x^2-36)<= 0 is -6<x<=-4\lor 0<= x<6