What are the solutions to the equation (x-8)(2x+9)=0 ?

The solutions to the equation (x-8)(2x+9)=0 are x=8,x=-9/2

Find the zeros of (x-8)(2x+9)=0

The zeros of (x-8)(2x+9)=0 are x=8,x=-9/2

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(x - 8) (2 x + 9) = 0

x = 8, x = - \frac{9}{2}

Decimal Notation

x = 8, x = - 4.5

Solution steps

(x - 8) (2 x + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 8 = 0 or 2 x + 9 = 0

Solve

x - 8 = 0 : x = 8

Solve

2 x + 9 = 0 : x = - \frac{9}{2}

The solutions to the quadratic equation are:

x = 8, x = - \frac{9}{2}

x + 5 = 3 x - 11

7 x - 4 = 4 x + 11

- 2 x + 1 < - 9

36 - 4 c - 3 c = 22

f = (- 3) - 6

What are the solutions to the equation (x-8)(2x+9)=0 ?
The solutions to the equation (x-8)(2x+9)=0 are x=8,x=-9/2
Find the zeros of (x-8)(2x+9)=0
The zeros of (x-8)(2x+9)=0 are x=8,x=-9/2