What are the solutions to the equation -14x^2+4x+14=-6x^2 ?

The solutions to the equation -14x^2+4x+14=-6x^2 are x=-(-1+sqrt(29))/4 ,x=(1+sqrt(29))/4

Find the zeros of -14x^2+4x+14=-6x^2

The zeros of -14x^2+4x+14=-6x^2 are x=-(-1+sqrt(29))/4 ,x=(1+sqrt(29))/4

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- 14 x^{2} + 4 x + 14 = - 6 x^{2}

x = - \frac{- 1 + 29}{4}, x = \frac{1 + 29}{4}

Decimal Notation

x = - 1.09629 \dots, x = 1.59629 \dots

Solution steps

- 14 x^{2} + 4 x + 14 = - 6 x^{2}

Move

6 x^{2}

to the left side

- 8 x^{2} + 4 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 8 ) \cdot 14}{2 ( - 8 )}

4^{2} - 4 (- 8) \cdot 14 = 429

x_{1, 2} = \frac{- 4 \pm 4 29}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- 4 + 4 29}{2 ( - 8 )}, x_{2} = \frac{- 4 - 4 29}{2 ( - 8 )}

x = \frac{- 4 + 4 29}{2 ( - 8 )} : - \frac{- 1 + 29}{4}

x = \frac{- 4 - 4 29}{2 ( - 8 )} : \frac{1 + 29}{4}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 29}{4}, x = \frac{1 + 29}{4}

2 x - 2 \leq 2

5 - \frac{1}{2} x = 4

3 x - 27 = 51

\frac{1}{4} ∣ x + 2 ∣ + 7 = 5

- 6 + \frac{x}{4} = - 5

What are the solutions to the equation -14x^2+4x+14=-6x^2 ?
The solutions to the equation -14x^2+4x+14=-6x^2 are x=-(-1+sqrt(29))/4 ,x=(1+sqrt(29))/4
Find the zeros of -14x^2+4x+14=-6x^2
The zeros of -14x^2+4x+14=-6x^2 are x=-(-1+sqrt(29))/4 ,x=(1+sqrt(29))/4