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Popular >

2|v-7|-4>= 42

Solution

2 ∣ v - 7 ∣ - 4 \geq 42

Solution

v \leq - 16 or v \geq 30

+1

Interval Notation

(- \infty, - 16] \cup [30, \infty)

Solution steps

2 ∣ v - 7 ∣ - 4 \geq 42

Move

4

to the right side

2 ∣ v - 7 ∣ \geq 46

Divide both sides by

2

∣ v - 7 ∣ \geq 23

Apply absolute rule: If

∣ u ∣ \geq a, a > 0

then

u \leq - a

or

u \geq a

v - 7 \leq - 23 or v - 7 \geq 23

v - 7 \leq - 23 or v - 7 \geq 23

v \leq - 16 or v \geq 30

Popular Examples

12x^2-240x+900=0

12 x^{2} - 240 x + 900 = 0

2 x^{2} = - 3 x

\frac{n}{3} = 2

simplify (7n)/(24n^3-64n^2)*(9n-24)/(7n)simplify

\frac{7 n}{24 n ^{3} - 64 n ^{2}} \cdot \frac{9 n - 24}{7 n}

simplify 8^{1/3}simplify

8^{\frac{1}{3}}

Frequently Asked Questions (FAQ)

What is 2|v-7|-4>= 42 ?
The solution to 2|v-7|-4>= 42 is v<=-16\lor v>= 30