What is factor 18c^3d^4-63c^2d^5+9cd^3 ?

The solution to factor 18c^3d^4-63c^2d^5+9cd^3 is 9cd^3(2c^2d-7cd^2+1)

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factor 18c^3d^4-63c^2d^5+9cd^3

factor

18 c^{3} d^{4} - 63 c^{2} d^{5} + 9 c d^{3}

9 c d^{3} (2 c^{2} d - 7 c d^{2} + 1)

Solution steps

18 c^{3} d^{4} - 63 c^{2} d^{5} + 9 c d^{3}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

c^{3} d^{4} = c c^{2} d^{3} d, c^{2} d^{5} = cc d^{3} d^{2}

= 18 c c^{2} d^{3} d - 63 cc d^{3} d^{2} + 9 c d^{3}

Rewrite

- 63

7 \cdot 9

Rewrite

18

2 \cdot 9

= 2 \cdot 9 c c^{2} d^{3} d + 7 \cdot 9 cc d^{3} d^{2} + 9 c d^{3}

Factor out common term

9 c d^{3}

= 9 c d^{3} (2 c^{2} d - 7 c d^{2} + 1)

- 1 > - 2

\frac{3}{x - 3} \leq 1

∣ 3 x - 1 ∣ < 4

16 z^{2} - 64 z + 73 = 0

What is factor 18c^3d^4-63c^2d^5+9cd^3 ?
The solution to factor 18c^3d^4-63c^2d^5+9cd^3 is 9cd^3(2c^2d-7cd^2+1)