What is factor 125+w^3 ?

The solution to factor 125+w^3 is (w+5)(w^2-5w+25)

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factor 125+w^3

factor

125 + w^{3}

(w + 5) (w^{2} - 5 w + 25)

Solution steps

125 + w^{3}

Write in the standard form

= w^{3} + 125

Rewrite

125

5^{3}

= w^{3} + 5^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

w^{3} + 5^{3} = (w + 5) (w^{2} - 5 w + 5^{2})

= (w + 5) (w^{2} - 5 w + 5^{2})

5^{2} = 25

= (w + 5) (w^{2} - 5 w + 25)

- 3 \leq \frac{2 x - 5}{3} < 5

v = \frac{4}{3} π 3^{3}

(2 x - 3)^{2} + x^{2} = (3 x + 1) (3 x - 1) - 6

x^{2} + 2 - 6

1000 (0.5)^{\frac{80}{30}}