What is (40-8x)/(x^2)<= 0 ?

The solution to (40-8x)/(x^2) = 5

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(40-8x)/(x^2)<= 0

\frac{40 - 8 x}{x ^{2}} \leq 0

x \geq 5

Interval Notation

[5, \infty)

Solution steps

\frac{40 - 8 x}{x ^{2}} \leq 0

Factor

\frac{40 - 8 x}{x ^{2}} : \frac{- 8 ( x - 5 )}{x ^{2}}

\frac{- 8 ( x - 5 )}{x ^{2}} \leq 0

Multiply both sides by

- 1

(reverse the inequality)

\frac{( - 8 ( x - 5 ) ) ( - 1 )}{x ^{2}} \geq 0 \cdot (- 1)

Simplify

\frac{8 ( x - 5 )}{x ^{2}} \geq 0

Divide both sides by

8

\frac{\frac{8 ( x - 5 )}{x ^{2}}}{8} \geq \frac{0}{8}

Simplify

\frac{x - 5}{x ^{2}} \geq 0

Identify the intervals

x \geq 5

- 2 x \leq - 8 or - 2 x \geq 0

7 x + 9 - 10 x = - 18

6147

9 + 3 x - 1 = 10 + 3 x

\frac{99 \cdot 9.81}{2 ( 0.05 ) ^{2}}