What are the solutions to the equation 30+q^2=396 ?

The solutions to the equation 30+q^2=396 are q=sqrt(366),q=-sqrt(366)

Find the zeros of 30+q^2=396

The zeros of 30+q^2=396 are q=sqrt(366),q=-sqrt(366)

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30 + q^{2} = 396

q = 366, q = - 366

Decimal Notation

q = 19.13112 \dots, q = - 19.13112 \dots

Solution steps

30 + q^{2} = 396

Move

30

to the right side

q^{2} = 366

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

q = 366, q = - 366

2 x^{2} - 6 x + 3 \leq 0

1 - \frac{12}{52}

\frac{6}{7} x - \frac{1}{8} \leq \frac{11}{14} x - \frac{8}{7}

3 x - 4 = - 13

\frac{5 x}{4} + \frac{x}{3} = - 2

What are the solutions to the equation 30+q^2=396 ?
The solutions to the equation 30+q^2=396 are q=sqrt(366),q=-sqrt(366)
Find the zeros of 30+q^2=396
The zeros of 30+q^2=396 are q=sqrt(366),q=-sqrt(366)