What are the solutions to the equation 4m^2+7m=6 ?

The solutions to the equation 4m^2+7m=6 are m=(-7+sqrt(145))/8 ,m=(-7-sqrt(145))/8

Find the zeros of 4m^2+7m=6

The zeros of 4m^2+7m=6 are m=(-7+sqrt(145))/8 ,m=(-7-sqrt(145))/8

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4 m^{2} + 7 m = 6

m = \frac{- 7 + 145}{8}, m = \frac{- 7 - 145}{8}

Decimal Notation

m = 0.63019 \dots, m = - 2.38019 \dots

Solution steps

4 m^{2} + 7 m = 6

Move

6

to the left side

4 m^{2} + 7 m - 6 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

7^{2} - 4 \cdot 4 (- 6) = 145

m_{1, 2} = \frac{- 7 \pm 145}{2 \cdot 4}

Separate the solutions

m_{1} = \frac{- 7 + 145}{2 \cdot 4}, m_{2} = \frac{- 7 - 145}{2 \cdot 4}

m = \frac{- 7 + 145}{2 \cdot 4} : \frac{- 7 + 145}{8}

m = \frac{- 7 - 145}{2 \cdot 4} : \frac{- 7 - 145}{8}

The solutions to the quadratic equation are:

m = \frac{- 7 + 145}{8}, m = \frac{- 7 - 145}{8}

7 x = 4 x + 27

\frac{5}{2} \cdot \frac{1}{2}

p^{5} (m - 8 n) + q (m - 8 n)

2 a^{2} + 7 a + 3

- 2 (\frac{4}{7})^{0}

What are the solutions to the equation 4m^2+7m=6 ?
The solutions to the equation 4m^2+7m=6 are m=(-7+sqrt(145))/8 ,m=(-7-sqrt(145))/8
Find the zeros of 4m^2+7m=6
The zeros of 4m^2+7m=6 are m=(-7+sqrt(145))/8 ,m=(-7-sqrt(145))/8