What is factor (x+1)^2-5 ?

The solution to factor (x+1)^2-5 is (x+1+sqrt(5))(x+1-sqrt(5))

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factor (x+1)^2-5

factor

(x + 1)^{2} - 5

(x + 1 + 5) (x + 1 - 5)

Solution steps

(x + 1)^{2} - 5

Apply radical rule:

a = (a)^{2}

5 = (5)^{2}

= (x + 1)^{2} - (5)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(x + 1)^{2} - (5)^{2} = ((x + 1) + 5) ((x + 1) - 5)

= ((x + 1) + 5) ((x + 1) - 5)

Refine

= (x + 1 + 5) (x + 1 - 5)

x^{3} - 6 x^{2} + x + 34

6 x - 12 = 0

6 b^{2} a - 36 ba - 162 a

0.6 r = 4.5

2 x^{2} + 6 x = - 5

What is factor (x+1)^2-5 ?
The solution to factor (x+1)^2-5 is (x+1+sqrt(5))(x+1-sqrt(5))