What are the solutions to the equation 4r^2-13r+6=0 ?

The solutions to the equation 4r^2-13r+6=0 are r=(13+sqrt(73))/8 ,r=(13-sqrt(73))/8

Find the zeros of 4r^2-13r+6=0

The zeros of 4r^2-13r+6=0 are r=(13+sqrt(73))/8 ,r=(13-sqrt(73))/8

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4 r^{2} - 13 r + 6 = 0

r = \frac{13 + 73}{8}, r = \frac{13 - 73}{8}

Decimal Notation

r = 2.69300 \dots, r = 0.55699 \dots

Solution steps

4 r^{2} - 13 r + 6 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 4 \cdot 6}{2 \cdot 4}

(- 13)^{2} - 4 \cdot 4 \cdot 6 = 73

r_{1, 2} = \frac{- ( - 13 ) \pm 73}{2 \cdot 4}

Separate the solutions

r_{1} = \frac{- ( - 13 ) + 73}{2 \cdot 4}, r_{2} = \frac{- ( - 13 ) - 73}{2 \cdot 4}

r = \frac{- ( - 13 ) + 73}{2 \cdot 4} : \frac{13 + 73}{8}

r = \frac{- ( - 13 ) - 73}{2 \cdot 4} : \frac{13 - 73}{8}

The solutions to the quadratic equation are:

r = \frac{13 + 73}{8}, r = \frac{13 - 73}{8}

- \frac{11}{2} + 3

\frac{x ^{5}}{x ^{10}}

8 x^{2} + 59 x + 21

x^{2} - 2 x - 8 \geq 0

What are the solutions to the equation 4r^2-13r+6=0 ?
The solutions to the equation 4r^2-13r+6=0 are r=(13+sqrt(73))/8 ,r=(13-sqrt(73))/8
Find the zeros of 4r^2-13r+6=0
The zeros of 4r^2-13r+6=0 are r=(13+sqrt(73))/8 ,r=(13-sqrt(73))/8