What are the solutions to the equation 3k^2+72=33k ?

The solutions to the equation 3k^2+72=33k are k=8,k=3

Find the zeros of 3k^2+72=33k

The zeros of 3k^2+72=33k are k=8,k=3

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3 k^{2} + 72 = 33 k

k = 8, k = 3

Solution steps

3 k^{2} + 72 = 33 k

Move

33 k

to the left side

3 k^{2} + 72 - 33 k = 0

Write in the standard form

a x^{2} + b x + c = 0

3 k^{2} - 33 k + 72 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 33 ) \pm ( - 33 ) ^{2} - 4 \cdot 3 \cdot 72}{2 \cdot 3}

(- 33)^{2} - 4 \cdot 3 \cdot 72 = 15

k_{1, 2} = \frac{- ( - 33 ) \pm 15}{2 \cdot 3}

Separate the solutions

k_{1} = \frac{- ( - 33 ) + 15}{2 \cdot 3}, k_{2} = \frac{- ( - 33 ) - 15}{2 \cdot 3}

k = \frac{- ( - 33 ) + 15}{2 \cdot 3} : 8

k = \frac{- ( - 33 ) - 15}{2 \cdot 3} : 3

The solutions to the quadratic equation are:

k = 8, k = 3

9 x^{2} - 12 x + 7 = 0

c^{2} - 25

(5 - 1)^{2}

a x + a - x - 1

x^{2} + 2 x - 13 = 0

What are the solutions to the equation 3k^2+72=33k ?
The solutions to the equation 3k^2+72=33k are k=8,k=3
Find the zeros of 3k^2+72=33k
The zeros of 3k^2+72=33k are k=8,k=3