What are the solutions to the equation a^2+4a+5=0 ?

The solutions to the equation a^2+4a+5=0 are a=-2+i,a=-2-i

Find the zeros of a^2+4a+5=0

The zeros of a^2+4a+5=0 are a=-2+i,a=-2-i

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a^{2} + 4 a + 5 = 0

a = - 2 + i, a = - 2 - i

Solution steps

a^{2} + 4 a + 5 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 5 : 2 i

a_{1, 2} = \frac{- 4 \pm 2 i}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 4 + 2 i}{2 \cdot 1}, a_{2} = \frac{- 4 - 2 i}{2 \cdot 1}

a = \frac{- 4 + 2 i}{2 \cdot 1} : - 2 + i

a = \frac{- 4 - 2 i}{2 \cdot 1} : - 2 - i

The solutions to the quadratic equation are:

a = - 2 + i, a = - 2 - i

x^{2} (x + 9)^{2} \geq 0

- 3 - (- 3)

(x - 4)^{2} = 81

7 b = 6

31 \geq 2 v + 15

What are the solutions to the equation a^2+4a+5=0 ?
The solutions to the equation a^2+4a+5=0 are a=-2+i,a=-2-i
Find the zeros of a^2+4a+5=0
The zeros of a^2+4a+5=0 are a=-2+i,a=-2-i