What are the solutions to the equation 3x^2+2x-65=0 ?

The solutions to the equation 3x^2+2x-65=0 are x= 13/3 ,x=-5

Find the zeros of 3x^2+2x-65=0

The zeros of 3x^2+2x-65=0 are x= 13/3 ,x=-5

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3 x^{2} + 2 x - 65 = 0

x = \frac{13}{3}, x = - 5

Decimal Notation

x = 4.33333 \dots, x = - 5

Solution steps

3 x^{2} + 2 x - 65 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 65 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 65) = 28

x_{1, 2} = \frac{- 2 \pm 28}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 28}{2 \cdot 3}, x_{2} = \frac{- 2 - 28}{2 \cdot 3}

x = \frac{- 2 + 28}{2 \cdot 3} : \frac{13}{3}

x = \frac{- 2 - 28}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

x = \frac{13}{3}, x = - 5

x^{4} + 8 x^{2} + 16

\frac{14 x ^{6} y ^{5}}{7 x ^{8} y ^{8}}

(\frac{1}{x})^{3}

3 z^{2} + z - 2

7 x + 7 = \frac{3 x - 9}{4}

What are the solutions to the equation 3x^2+2x-65=0 ?
The solutions to the equation 3x^2+2x-65=0 are x= 13/3 ,x=-5
Find the zeros of 3x^2+2x-65=0
The zeros of 3x^2+2x-65=0 are x= 13/3 ,x=-5