What are the solutions to the equation 12^2+12^2=x^2 ?

The solutions to the equation 12^2+12^2=x^2 are x=12sqrt(2),x=-12sqrt(2)

Find the zeros of 12^2+12^2=x^2

The zeros of 12^2+12^2=x^2 are x=12sqrt(2),x=-12sqrt(2)

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1 2^{2} + 1 2^{2} = x^{2}

x = 122, x = - 122

Decimal Notation

x = 16.97056 \dots, x = - 16.97056 \dots

Solution steps

1 2^{2} + 1 2^{2} = x^{2}

Switch sides

x^{2} = 1 2^{2} + 1 2^{2}

Simplify

1 2^{2} + 1 2^{2} : 288

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 288, x = - 288

288 = 122

- 288 = - 122

x = 122, x = - 122

(7 - 2)^{2}

(7 + 2) (7 - 2)

- 3 \leq 2 x + 5 < 7

x^{2} \geq - 4 x

a^{2} + 6 a - 40

What are the solutions to the equation 12^2+12^2=x^2 ?
The solutions to the equation 12^2+12^2=x^2 are x=12sqrt(2),x=-12sqrt(2)
Find the zeros of 12^2+12^2=x^2
The zeros of 12^2+12^2=x^2 are x=12sqrt(2),x=-12sqrt(2)