What are the solutions to the equation -x^2-x+10=0 ?

The solutions to the equation -x^2-x+10=0 are x=-(1+sqrt(41))/2 ,x=(sqrt(41)-1)/2

Find the zeros of -x^2-x+10=0

The zeros of -x^2-x+10=0 are x=-(1+sqrt(41))/2 ,x=(sqrt(41)-1)/2

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- x^{2} - x + 10 = 0

x = - \frac{1 + 41}{2}, x = \frac{41 - 1}{2}

Decimal Notation

x = - 3.70156 \dots, x = 2.70156 \dots

Solution steps

- x^{2} - x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 10}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 10 = 41

x_{1, 2} = \frac{- ( - 1 ) \pm 41}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 41}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 41}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 41}{2 ( - 1 )} : - \frac{1 + 41}{2}

x = \frac{- ( - 1 ) - 41}{2 ( - 1 )} : \frac{41 - 1}{2}

The solutions to the quadratic equation are:

x = - \frac{1 + 41}{2}, x = \frac{41 - 1}{2}

x (x + 20) = - 100

- 16 t^{2} + 160 t = 0

x^{2} - 8 x \geq 0

150 = 6 x^{2}

a^{4} + 7 a^{2} + 6

What are the solutions to the equation -x^2-x+10=0 ?
The solutions to the equation -x^2-x+10=0 are x=-(1+sqrt(41))/2 ,x=(sqrt(41)-1)/2
Find the zeros of -x^2-x+10=0
The zeros of -x^2-x+10=0 are x=-(1+sqrt(41))/2 ,x=(sqrt(41)-1)/2