What are the solutions to the equation 2y^2+y+10=0 ?

The solutions to the equation 2y^2+y+10=0 are y=-1/4+i(sqrt(79))/4 ,y=-1/4-i(sqrt(79))/4

Find the zeros of 2y^2+y+10=0

The zeros of 2y^2+y+10=0 are y=-1/4+i(sqrt(79))/4 ,y=-1/4-i(sqrt(79))/4

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2 y^{2} + y + 10 = 0

y = - \frac{1}{4} + i \frac{79}{4}, y = - \frac{1}{4} - i \frac{79}{4}

Solution steps

2 y^{2} + y + 10 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 \cdot 10}{2 \cdot 2}

Simplify

1^{2} - 4 \cdot 2 \cdot 10 : 79 i

y_{1, 2} = \frac{- 1 \pm 79 i}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- 1 + 79 i}{2 \cdot 2}, y_{2} = \frac{- 1 - 79 i}{2 \cdot 2}

y = \frac{- 1 + 79 i}{2 \cdot 2} : - \frac{1}{4} + i \frac{79}{4}

y = \frac{- 1 - 79 i}{2 \cdot 2} : - \frac{1}{4} - i \frac{79}{4}

The solutions to the quadratic equation are:

y = - \frac{1}{4} + i \frac{79}{4}, y = - \frac{1}{4} - i \frac{79}{4}

lo g_{36} (\frac{1}{6})

\frac{48 x ^{3}}{3 x y ^{2}}

3 = y + 6

3 x^{2} + 10 x + 7

x^{3}

What are the solutions to the equation 2y^2+y+10=0 ?
The solutions to the equation 2y^2+y+10=0 are y=-1/4+i(sqrt(79))/4 ,y=-1/4-i(sqrt(79))/4
Find the zeros of 2y^2+y+10=0
The zeros of 2y^2+y+10=0 are y=-1/4+i(sqrt(79))/4 ,y=-1/4-i(sqrt(79))/4