What are the solutions to the equation 2w^2-15w+19=0 ?

The solutions to the equation 2w^2-15w+19=0 are w=(15+sqrt(73))/4 ,w=(15-sqrt(73))/4

Find the zeros of 2w^2-15w+19=0

The zeros of 2w^2-15w+19=0 are w=(15+sqrt(73))/4 ,w=(15-sqrt(73))/4

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2 w^{2} - 15 w + 19 = 0

w = \frac{15 + 73}{4}, w = \frac{15 - 73}{4}

Decimal Notation

w = 5.88600 \dots, w = 1.61399 \dots

Solution steps

2 w^{2} - 15 w + 19 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 2 \cdot 19}{2 \cdot 2}

(- 15)^{2} - 4 \cdot 2 \cdot 19 = 73

w_{1, 2} = \frac{- ( - 15 ) \pm 73}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 15 ) + 73}{2 \cdot 2}, w_{2} = \frac{- ( - 15 ) - 73}{2 \cdot 2}

w = \frac{- ( - 15 ) + 73}{2 \cdot 2} : \frac{15 + 73}{4}

w = \frac{- ( - 15 ) - 73}{2 \cdot 2} : \frac{15 - 73}{4}

The solutions to the quadratic equation are:

w = \frac{15 + 73}{4}, w = \frac{15 - 73}{4}

3 x^{2} + 5 x + 2 = 0

4.57 E 15 x^{2} - 3300000 x - 0.00125 = 0

2 x^{3} + x^{2} - 3 x + 1

x^{3} - 5 x^{2} < 6 x

25 \cdot 9

What are the solutions to the equation 2w^2-15w+19=0 ?
The solutions to the equation 2w^2-15w+19=0 are w=(15+sqrt(73))/4 ,w=(15-sqrt(73))/4
Find the zeros of 2w^2-15w+19=0
The zeros of 2w^2-15w+19=0 are w=(15+sqrt(73))/4 ,w=(15-sqrt(73))/4