What are the solutions to the equation x^2+12x+23=0 ?

The solutions to the equation x^2+12x+23=0 are x=-6+sqrt(13),x=-6-sqrt(13)

Find the zeros of x^2+12x+23=0

The zeros of x^2+12x+23=0 are x=-6+sqrt(13),x=-6-sqrt(13)

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x^{2} + 12 x + 23 = 0

x = - 6 + 13, x = - 6 - 13

Solution steps

x^{2} + 12 x + 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 23}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 23 = 213

x_{1, 2} = \frac{- 12 \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 13}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 13}{2 \cdot 1}

x = \frac{- 12 + 2 13}{2 \cdot 1} : - 6 + 13

x = \frac{- 12 - 2 13}{2 \cdot 1} : - 6 - 13

The solutions to the quadratic equation are:

x = - 6 + 13, x = - 6 - 13

- 0.3 (2 x - 5) = 0.7 (3 - x)

(\frac{9}{5})^{- 2}

3 m^{6} - 27 n^{4}

- 6 < \frac{w}{- 1} - 1

t^{2} - 19 t + 18 = 0

What are the solutions to the equation x^2+12x+23=0 ?
The solutions to the equation x^2+12x+23=0 are x=-6+sqrt(13),x=-6-sqrt(13)
Find the zeros of x^2+12x+23=0
The zeros of x^2+12x+23=0 are x=-6+sqrt(13),x=-6-sqrt(13)