What are the solutions to the equation 1=x^2-6x+9 ?

The solutions to the equation 1=x^2-6x+9 are x=4,x=2

Find the zeros of 1=x^2-6x+9

The zeros of 1=x^2-6x+9 are x=4,x=2

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1 = x^{2} - 6 x + 9

x = 4, x = 2

Solution steps

1 = x^{2} - 6 x + 9

Switch sides

x^{2} - 6 x + 9 = 1

Move

1

to the left side

x^{2} - 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 8 = 2

x_{1, 2} = \frac{- ( - 6 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2}{2 \cdot 1} : 4

x = \frac{- ( - 6 ) - 2}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 4, x = 2

\frac{5}{2 - i}

∣ 5 x + 9 ∣ = ∣ 9 x + 4 ∣

120 p^{3} n^{2} + 24 p^{2} n^{2} - 40 n^{2 p} - 8 n

\frac{8}{4 - 2}

x - 8 < - 1

What are the solutions to the equation 1=x^2-6x+9 ?
The solutions to the equation 1=x^2-6x+9 are x=4,x=2
Find the zeros of 1=x^2-6x+9
The zeros of 1=x^2-6x+9 are x=4,x=2