What are the solutions to the equation (y+2)^2=9 ?

The solutions to the equation (y+2)^2=9 are y=1,y=-5

Find the zeros of (y+2)^2=9

The zeros of (y+2)^2=9 are y=1,y=-5

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(y + 2)^{2} = 9

y = 1, y = - 5

Solution steps

(y + 2)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y + 2 = 9 : y = 1

Solve

y + 2 = - 9 : y = - 5

The solutions to the quadratic equation are:

y = 1, y = - 5

n^{2} = - 47

2 x - 6 = 10

- 3 x + 1 \geq 0

\frac{a - y}{w + n} \cdot \frac{w ^{2} - n ^{2}}{y - a}

What are the solutions to the equation (y+2)^2=9 ?
The solutions to the equation (y+2)^2=9 are y=1,y=-5
Find the zeros of (y+2)^2=9
The zeros of (y+2)^2=9 are y=1,y=-5