What are the solutions to the equation x^2+5=21 ?

The solutions to the equation x^2+5=21 are x=4,x=-4

Find the zeros of x^2+5=21

The zeros of x^2+5=21 are x=4,x=-4

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x^{2} + 5 = 21

x = 4, x = - 4

Solution steps

x^{2} + 5 = 21

Move

5

to the right side

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

\frac{5 ( 97 )}{129} + \frac{5 ( 11 )}{30} + 1

x^{2} + 15 x = 0

d + 36 - 3 d = 24

3 x - 5 < - 11 or 5 x + 1 \geq 6

4 y^{2} + 4 y + 1

What are the solutions to the equation x^2+5=21 ?
The solutions to the equation x^2+5=21 are x=4,x=-4
Find the zeros of x^2+5=21
The zeros of x^2+5=21 are x=4,x=-4