What are the solutions to the equation x(x+8)=-25 ?

The solutions to the equation x(x+8)=-25 are x=-4+3i,x=-4-3i

Find the zeros of x(x+8)=-25

The zeros of x(x+8)=-25 are x=-4+3i,x=-4-3i

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x (x + 8) = - 25

x = - 4 + 3 i, x = - 4 - 3 i

Solution steps

x (x + 8) = - 25

Expand

x (x + 8) : x^{2} + 8 x

x^{2} + 8 x = - 25

Move

25

to the left side

x^{2} + 8 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 25 : 6 i

x_{1, 2} = \frac{- 8 \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 6 i}{2 \cdot 1}, x_{2} = \frac{- 8 - 6 i}{2 \cdot 1}

x = \frac{- 8 + 6 i}{2 \cdot 1} : - 4 + 3 i

x = \frac{- 8 - 6 i}{2 \cdot 1} : - 4 - 3 i

The solutions to the quadratic equation are:

x = - 4 + 3 i, x = - 4 - 3 i

8 c^{6} + 19 c^{3} - 27

x^{2} + 12 x - 64

36 = y^{2}

9 x^{2} \cdot 9 y^{5}

- 1 - \frac{y}{8} = - 7

What are the solutions to the equation x(x+8)=-25 ?
The solutions to the equation x(x+8)=-25 are x=-4+3i,x=-4-3i
Find the zeros of x(x+8)=-25
The zeros of x(x+8)=-25 are x=-4+3i,x=-4-3i