What is 4sqrt(x)-2>20 ?

The solution to 4sqrt(x)-2>20 is x> 121/4

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4sqrt(x)-2>20

4 x - 2 > 20

x > \frac{121}{4}

Interval Notation

(\frac{121}{4}, \infty)

Decimal Notation

x > 30.25

Solution steps

4 x - 2 > 20

Move

2

to the right side

4 x > 22

Divide both sides by

4

x > \frac{11}{2}

Square both sides

(x)^{2} > (\frac{11}{2})^{2}

Simplify

x > (\frac{11}{2})^{2}

Expand

(\frac{11}{2})^{2} : \frac{121}{4}

x > \frac{121}{4}

Find singularity points

Find non-negative values for radicals:

x \geq 0

Combine the intervals

x > \frac{121}{4} and x \geq 0

Merge Overlapping Intervals

x > \frac{121}{4}

2 (3 x + 2) = 2 x - 1 + x

n^{2} - 25

3 a + 81

4 x - 5 x + 9 = 5 x - 9

\frac{- 1}{2 ( - 4 + 2 x )} = - 6 - 4 x