What are the solutions to the equation (3x+1)^2=5 ?

The solutions to the equation (3x+1)^2=5 are x=(sqrt(5)-1)/3 ,x=(-sqrt(5)-1)/3

Find the zeros of (3x+1)^2=5

The zeros of (3x+1)^2=5 are x=(sqrt(5)-1)/3 ,x=(-sqrt(5)-1)/3

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(3 x + 1)^{2} = 5

x = \frac{5 - 1}{3}, x = \frac{- 5 - 1}{3}

Decimal Notation

x = 0.41202 \dots, x = - 1.07868 \dots

Solution steps

(3 x + 1)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 1 = 5 : x = \frac{5 - 1}{3}

Solve

3 x + 1 = - 5 : x = \frac{- 5 - 1}{3}

The solutions to the quadratic equation are:

x = \frac{5 - 1}{3}, x = \frac{- 5 - 1}{3}

6 x^{2} - 6 x = 0

2 x^{2} + 21 x + 10

(2 x^{\frac{1}{2}} y^{\frac{3}{4}}) (3 x^{\frac{1}{4}})

- (x - 4) + (2 - x) = 6

5 r^{2} - 11 r = 12

What are the solutions to the equation (3x+1)^2=5 ?
The solutions to the equation (3x+1)^2=5 are x=(sqrt(5)-1)/3 ,x=(-sqrt(5)-1)/3
Find the zeros of (3x+1)^2=5
The zeros of (3x+1)^2=5 are x=(sqrt(5)-1)/3 ,x=(-sqrt(5)-1)/3