What are the solutions to the equation x^2-x+3=2x^2-5x-29 ?

The solutions to the equation x^2-x+3=2x^2-5x-29 are x=-4,x=8

Find the zeros of x^2-x+3=2x^2-5x-29

The zeros of x^2-x+3=2x^2-5x-29 are x=-4,x=8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - x + 3 = 2 x^{2} - 5 x - 29

x = - 4, x = 8

Solution steps

x^{2} - x + 3 = 2 x^{2} - 5 x - 29

Move

29

to the left side

x^{2} - x + 32 = 2 x^{2} - 5 x

Move

5 x

to the left side

x^{2} + 4 x + 32 = 2 x^{2}

Move

2 x^{2}

to the left side

- x^{2} + 4 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) \cdot 32}{2 ( - 1 )}

4^{2} - 4 (- 1) \cdot 32 = 12

x_{1, 2} = \frac{- 4 \pm 12}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 12}{2 ( - 1 )}, x_{2} = \frac{- 4 - 12}{2 ( - 1 )}

x = \frac{- 4 + 12}{2 ( - 1 )} : - 4

x = \frac{- 4 - 12}{2 ( - 1 )} : 8

The solutions to the quadratic equation are:

x = - 4, x = 8

12 m n^{2} + 6 m^{2} n + 2 m

- 4 x + 60 < 72

2 a^{2} - 9 a - 5

x^{2} - 10 x - 24

∣ x + 7 ∣ \leq 8

What are the solutions to the equation x^2-x+3=2x^2-5x-29 ?
The solutions to the equation x^2-x+3=2x^2-5x-29 are x=-4,x=8
Find the zeros of x^2-x+3=2x^2-5x-29
The zeros of x^2-x+3=2x^2-5x-29 are x=-4,x=8