What are the solutions to the equation 26=x^2-2x+2 ?

The solutions to the equation 26=x^2-2x+2 are x=6,x=-4

Find the zeros of 26=x^2-2x+2

The zeros of 26=x^2-2x+2 are x=6,x=-4

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26 = x^{2} - 2 x + 2

x = 6, x = - 4

Solution steps

26 = x^{2} - 2 x + 2

Switch sides

x^{2} - 2 x + 2 = 26

Move

26

to the left side

x^{2} - 2 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 24) = 10

x_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 1}

x = \frac{- ( - 2 ) + 10}{2 \cdot 1} : 6

x = \frac{- ( - 2 ) - 10}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 6, x = - 4

10 a = 5

(1 + 2 i) + (3 + 4 i)

(\frac{1}{w} (\frac{s}{t} + w - 1))^{2}

x + 3 (x - 2) = 10

(18 - 40 i) - (- 9 + 2 i)

What are the solutions to the equation 26=x^2-2x+2 ?
The solutions to the equation 26=x^2-2x+2 are x=6,x=-4
Find the zeros of 26=x^2-2x+2
The zeros of 26=x^2-2x+2 are x=6,x=-4