What are the solutions to the equation s^2-11s+18=0 ?

The solutions to the equation s^2-11s+18=0 are s=9,s=2

Find the zeros of s^2-11s+18=0

The zeros of s^2-11s+18=0 are s=9,s=2

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s^{2} - 11 s + 18 = 0

s = 9, s = 2

Solution steps

s^{2} - 11 s + 18 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 18 = 7

s_{1, 2} = \frac{- ( - 11 ) \pm 7}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 11 ) + 7}{2 \cdot 1}, s_{2} = \frac{- ( - 11 ) - 7}{2 \cdot 1}

s = \frac{- ( - 11 ) + 7}{2 \cdot 1} : 9

s = \frac{- ( - 11 ) - 7}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

s = 9, s = 2

14 - 2 ∣ x + 4 ∣ > 8

\frac{a - 1}{3} + \frac{2 a}{6} + \frac{3 a + 4}{12}

\frac{y}{4} = 6

2 x^{2} - x - 1 \geq 0

2 p^{2} + 12 p + 14 = 0

What are the solutions to the equation s^2-11s+18=0 ?
The solutions to the equation s^2-11s+18=0 are s=9,s=2
Find the zeros of s^2-11s+18=0
The zeros of s^2-11s+18=0 are s=9,s=2