What are the solutions to the equation m^2-5m=-10 ?

The solutions to the equation m^2-5m=-10 are m= 5/2+i(sqrt(15))/2 ,m= 5/2-i(sqrt(15))/2

Find the zeros of m^2-5m=-10

The zeros of m^2-5m=-10 are m= 5/2+i(sqrt(15))/2 ,m= 5/2-i(sqrt(15))/2

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m^{2} - 5 m = - 10

m = \frac{5}{2} + i \frac{15}{2}, m = \frac{5}{2} - i \frac{15}{2}

Solution steps

m^{2} - 5 m = - 10

Move

10

to the left side

m^{2} - 5 m + 10 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

(- 5)^{2} - 4 \cdot 1 \cdot 10 : 15 i

m_{1, 2} = \frac{- ( - 5 ) \pm 15 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 5 ) + 15 i}{2 \cdot 1}, m_{2} = \frac{- ( - 5 ) - 15 i}{2 \cdot 1}

m = \frac{- ( - 5 ) + 15 i}{2 \cdot 1} : \frac{5}{2} + i \frac{15}{2}

m = \frac{- ( - 5 ) - 15 i}{2 \cdot 1} : \frac{5}{2} - i \frac{15}{2}

The solutions to the quadratic equation are:

m = \frac{5}{2} + i \frac{15}{2}, m = \frac{5}{2} - i \frac{15}{2}

(9)^{2}

4 x - (68 - x) 6 = 22

\frac{10}{4}

5 x y + 10 x k u a s a^{2} y

3 x^{2} - x + 22 = 5

What are the solutions to the equation m^2-5m=-10 ?
The solutions to the equation m^2-5m=-10 are m= 5/2+i(sqrt(15))/2 ,m= 5/2-i(sqrt(15))/2
Find the zeros of m^2-5m=-10
The zeros of m^2-5m=-10 are m= 5/2+i(sqrt(15))/2 ,m= 5/2-i(sqrt(15))/2