What are the solutions to the equation X^2+3X-4=0 ?

The solutions to the equation X^2+3X-4=0 are X=1,X=-4

Find the zeros of X^2+3X-4=0

The zeros of X^2+3X-4=0 are X=1,X=-4

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X^{2} + 3 X - 4 = 0

X = 1, X = - 4

Solution steps

X^{2} + 3 X - 4 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 4) = 5

X_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 3 + 5}{2 \cdot 1}, X_{2} = \frac{- 3 - 5}{2 \cdot 1}

X = \frac{- 3 + 5}{2 \cdot 1} : 1

X = \frac{- 3 - 5}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

X = 1, X = - 4

8 x y^{5} - 16 x^{2} y^{3} + 20 x^{4} y^{4}

\frac{2}{1 + i}

∣ x + i y ∣

8 > x

d^{2} - 20 d + 100

What are the solutions to the equation X^2+3X-4=0 ?
The solutions to the equation X^2+3X-4=0 are X=1,X=-4
Find the zeros of X^2+3X-4=0
The zeros of X^2+3X-4=0 are X=1,X=-4