What are the solutions to the equation 2x-x^2=-6 ?

The solutions to the equation 2x-x^2=-6 are x=1-sqrt(7),x=1+sqrt(7)

Find the zeros of 2x-x^2=-6

The zeros of 2x-x^2=-6 are x=1-sqrt(7),x=1+sqrt(7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x - x^{2} = - 6

x = 1 - 7, x = 1 + 7

Decimal Notation

x = - 1.64575 \dots, x = 3.64575 \dots

Solution steps

2 x - x^{2} = - 6

Move

6

to the left side

2 x - x^{2} + 6 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 2 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 6}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 6 = 27

x_{1, 2} = \frac{- 2 \pm 2 7}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 7}{2 ( - 1 )}, x_{2} = \frac{- 2 - 2 7}{2 ( - 1 )}

x = \frac{- 2 + 2 7}{2 ( - 1 )} : 1 - 7

x = \frac{- 2 - 2 7}{2 ( - 1 )} : 1 + 7

The solutions to the quadratic equation are:

x = 1 - 7, x = 1 + 7

2 x^{2} + 5 x

\frac{1}{5} (15 + 10 k)

6 n - 12 (6 - n) \leq 9 (n - 8) + 9 n

- 210 \cdot 320

(- x^{2})^{5}

What are the solutions to the equation 2x-x^2=-6 ?
The solutions to the equation 2x-x^2=-6 are x=1-sqrt(7),x=1+sqrt(7)
Find the zeros of 2x-x^2=-6
The zeros of 2x-x^2=-6 are x=1-sqrt(7),x=1+sqrt(7)