What are the solutions to the equation 5/8 x^2-x-12=-x^2-2x+234 ?

The solutions to the equation 5/8 x^2-x-12=-x^2-2x+234 are x=12,x=-164/13

Find the zeros of 5/8 x^2-x-12=-x^2-2x+234

The zeros of 5/8 x^2-x-12=-x^2-2x+234 are x=12,x=-164/13

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\frac{5}{8} x^{2} - x - 12 = - x^{2} - 2 x + 234

x = 12, x = - \frac{164}{13}

Decimal Notation

x = 12, x = - 12.61538 \dots

Solution steps

\frac{5}{8} x^{2} - x - 12 = - x^{2} - 2 x + 234

Multiply both sides by

8

5 x^{2} - 8 x - 96 = - 8 x^{2} - 16 x + 1872

Move

1872

to the left side

5 x^{2} - 8 x - 1968 = - 8 x^{2} - 16 x

Move

16 x

to the left side

5 x^{2} + 8 x - 1968 = - 8 x^{2}

Move

8 x^{2}

to the left side

13 x^{2} + 8 x - 1968 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 13 ( - 1968 )}{2 \cdot 13}

8^{2} - 4 \cdot 13 (- 1968) = 320

x_{1, 2} = \frac{- 8 \pm 320}{2 \cdot 13}

Separate the solutions

x_{1} = \frac{- 8 + 320}{2 \cdot 13}, x_{2} = \frac{- 8 - 320}{2 \cdot 13}

x = \frac{- 8 + 320}{2 \cdot 13} : 12

x = \frac{- 8 - 320}{2 \cdot 13} : - \frac{164}{13}

The solutions to the quadratic equation are:

x = 12, x = - \frac{164}{13}

3 y + 5 < 20

x^{2} - 2 x y - 3 y^{2}

\frac{1}{( 3 k ) ^{5}}

30 n^{2} b - 87 nb + 30 b

64 y^{2} - x^{3} y^{2}

What are the solutions to the equation 5/8 x^2-x-12=-x^2-2x+234 ?
The solutions to the equation 5/8 x^2-x-12=-x^2-2x+234 are x=12,x=-164/13
Find the zeros of 5/8 x^2-x-12=-x^2-2x+234
The zeros of 5/8 x^2-x-12=-x^2-2x+234 are x=12,x=-164/13