What are the solutions to the equation 5-5x^2=-230 ?

The solutions to the equation 5-5x^2=-230 are x=sqrt(47),x=-sqrt(47)

Find the zeros of 5-5x^2=-230

The zeros of 5-5x^2=-230 are x=sqrt(47),x=-sqrt(47)

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5 - 5 x^{2} = - 230

x = 47, x = - 47

Decimal Notation

x = 6.85565 \dots, x = - 6.85565 \dots

Solution steps

5 - 5 x^{2} = - 230

Move

5

to the right side

- 5 x^{2} = - 235

Divide both sides by

- 5

x^{2} = 47

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 47, x = - 47

2 x^{2} - 15 x + 7 = 0

(x + 4)^{2} - 25 = 0

17 - \frac{1}{9} x = 10

12 - x \cdot x - 12

lo g_{\frac{1}{3}} (\frac{1}{3})

What are the solutions to the equation 5-5x^2=-230 ?
The solutions to the equation 5-5x^2=-230 are x=sqrt(47),x=-sqrt(47)
Find the zeros of 5-5x^2=-230
The zeros of 5-5x^2=-230 are x=sqrt(47),x=-sqrt(47)