What are the solutions to the equation 3x^2+x=2 ?

The solutions to the equation 3x^2+x=2 are x= 2/3 ,x=-1

Find the zeros of 3x^2+x=2

The zeros of 3x^2+x=2 are x= 2/3 ,x=-1

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3 x^{2} + x = 2

x = \frac{2}{3}, x = - 1

Decimal Notation

x = 0.66666 \dots, x = - 1

Solution steps

3 x^{2} + x = 2

Move

2

to the left side

3 x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 2) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 3}, x_{2} = \frac{- 1 - 5}{2 \cdot 3}

x = \frac{- 1 + 5}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 1 - 5}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 1

(\frac{3}{5})^{- 1}

(x - 1)^{\frac{7}{2}} - (x - 1)^{\frac{3}{2}}

∣ x - 9 ∣ = 9

x^{2} + 11 x + 28 \leq 0

2 x + 42 + x - 7 + x - 7 = 180

What are the solutions to the equation 3x^2+x=2 ?
The solutions to the equation 3x^2+x=2 are x= 2/3 ,x=-1
Find the zeros of 3x^2+x=2
The zeros of 3x^2+x=2 are x= 2/3 ,x=-1