What are the solutions to the equation 2x^2+5x=3 ?

The solutions to the equation 2x^2+5x=3 are x= 1/2 ,x=-3

Find the zeros of 2x^2+5x=3

The zeros of 2x^2+5x=3 are x= 1/2 ,x=-3

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2 x^{2} + 5 x = 3

x = \frac{1}{2}, x = - 3

Decimal Notation

x = 0.5, x = - 3

Solution steps

2 x^{2} + 5 x = 3

Move

3

to the left side

2 x^{2} + 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 3) = 7

x_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 7}{2 \cdot 2}, x_{2} = \frac{- 5 - 7}{2 \cdot 2}

x = \frac{- 5 + 7}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 5 - 7}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 3

x^{3} - 8 x^{2} + 5 x + 14

0 - 2 y = 8

y^{- \frac{4}{3}}

x^{2} + 2 x^{4} - 11 x^{3} - 40 x^{2} - 44 x - 16

lo g_{4} (\frac{1}{2})

What are the solutions to the equation 2x^2+5x=3 ?
The solutions to the equation 2x^2+5x=3 are x= 1/2 ,x=-3
Find the zeros of 2x^2+5x=3
The zeros of 2x^2+5x=3 are x= 1/2 ,x=-3