What is (m^4-n^4)/(m^2+n^2) ?

The solution to (m^4-n^4)/(m^2+n^2) is m^2-n^2

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simplify (m^4-n^4)/(m^2+n^2)

simplify

\frac{m ^{4} - n ^{4}}{m ^{2} + n ^{2}}

m^{2} - n^{2}

Solution steps

\frac{m ^{4} - n ^{4}}{m ^{2} + n ^{2}}

Factor

m^{4} - n^{4} : (m^{2} + n^{2}) (m^{2} - n^{2})

= \frac{( m ^{2} + n ^{2} ) ( m ^{2} - n ^{2} )}{m ^{2} + n ^{2}}

Cancel the common factor:

m^{2} + n^{2}

= m^{2} - n^{2}

2 m^{2} - m - 15 = 0

(12 x + 7)^{2} - 4 (2 x - 1)^{2}

\frac{1}{1 - ( \frac{1}{2} ) ^{2}}

8 - 4 ∣ 1 - x ∣ = - 24