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Popular >

4|2x-7|+5>19

Solution

4 ∣ 2 x - 7 ∣ + 5 > 19

Solution

x < \frac{7}{4} or x > \frac{21}{4}

+2

Solution steps

4 ∣ 2 x - 7 ∣ + 5 > 19

Move

5

to the right side

4 ∣ 2 x - 7 ∣ > 14

Divide both sides by

4

∣ 2 x - 7 ∣ > \frac{7}{2}

Apply absolute rule: If

∣ u ∣ > a, a > 0

then

u < - a

or

u > a

2 x - 7 < - \frac{7}{2} or 2 x - 7 > \frac{7}{2}

2 x - 7 < - \frac{7}{2} or 2 x - 7 > \frac{7}{2}

x < \frac{7}{4} or x > \frac{21}{4}

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\frac{10 !}{( 10 - 3 ) ! 3 !}

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x^{2} + 3 x < 1 - x

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- (\frac{4}{3})^{3}

Frequently Asked Questions (FAQ)

What is 4|2x-7|+5>19 ?
The solution to 4|2x-7|+5>19 is x< 7/4 \lor x> 21/4