What are the solutions to the equation 2(x+3)(2x-1)=0 ?

The solutions to the equation 2(x+3)(2x-1)=0 are x=-3,x= 1/2

Find the zeros of 2(x+3)(2x-1)=0

The zeros of 2(x+3)(2x-1)=0 are x=-3,x= 1/2

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2 (x + 3) (2 x - 1) = 0

x = - 3, x = \frac{1}{2}

Decimal Notation

x = - 3, x = 0.5

Solution steps

2 (x + 3) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or 2 x - 1 = 0

Solve

x + 3 = 0 : x = - 3

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions to the quadratic equation are:

x = - 3, x = \frac{1}{2}

9 k - 2 < 3 k + 10

∣ x - 8 ∣ < 3

63 + 2 z - z^{2}

4 x - 18 = 2 x - 2

∣ x ∣ = 18

What are the solutions to the equation 2(x+3)(2x-1)=0 ?
The solutions to the equation 2(x+3)(2x-1)=0 are x=-3,x= 1/2
Find the zeros of 2(x+3)(2x-1)=0
The zeros of 2(x+3)(2x-1)=0 are x=-3,x= 1/2