What are the solutions to the equation 5^2+b^2=4^2 ?

The solutions to the equation 5^2+b^2=4^2 are b=3i,b=-3i

Find the zeros of 5^2+b^2=4^2

The zeros of 5^2+b^2=4^2 are b=3i,b=-3i

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5^{2} + b^{2} = 4^{2}

b = 3 i, b = - 3 i

Solution steps

5^{2} + b^{2} = 4^{2}

Move

5^{2}

to the right side

b^{2} = - 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = - 9, b = - - 9

- 9 = 3 i

- - 9 = - 3 i

b = 3 i, b = - 3 i

- 3 x^{2} + 108

15 \cdot \frac{300}{1200}

\frac{5 + 3 \cdot 8 - 12}{4} = 3

2 i^{4}

5 v + 10 \leq - 4 v

What are the solutions to the equation 5^2+b^2=4^2 ?
The solutions to the equation 5^2+b^2=4^2 are b=3i,b=-3i
Find the zeros of 5^2+b^2=4^2
The zeros of 5^2+b^2=4^2 are b=3i,b=-3i