What is (x-4)/2-(3x+1)/4 <= (-x)/8 ?

The solution to (x-4)/2-(3x+1)/4 =-18

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(x-4)/2-(3x+1)/4 <= (-x)/8

\frac{x - 4}{2} - \frac{3 x + 1}{4} \leq \frac{- x}{8}

x \geq - 18

Interval Notation

[- 18, \infty)

Solution steps

\frac{x - 4}{2} - \frac{3 x + 1}{4} \leq \frac{- x}{8}

Multiply by LCM

4 (x - 4) - 2 (3 x + 1) \leq - x

Expand

4 (x - 4) - 2 (3 x + 1) : - 2 x - 18

- 2 x - 18 \leq - x

Move

18

to the right side

- 2 x \leq - x + 18

Move

x

to the left side

- x \leq 18

Multiply both sides by

- 1

x \geq - 18

x^{2} - 4 \leq 2 x + 4

\frac{10 !}{( 10 - 5 ) ! 5 !}

5 x + 22 = 83

(- \frac{5}{3})^{3}

0. 9^{10}

What is (x-4)/2-(3x+1)/4 <= (-x)/8 ?
The solution to (x-4)/2-(3x+1)/4 <= (-x)/8 is x>=-18