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Popular >

simplify (b^{-1/9})^2

Solution

simplify

(b^{- \frac{1}{9}})^{2}

Solution

\frac{1}{b ^{\frac{2}{9}}}

Solution steps

(b^{- \frac{1}{9}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= b^{- \frac{1}{9} \cdot 2}

- \frac{1}{9} \cdot 2 = - \frac{2}{9}

= b^{- \frac{2}{9}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

b^{- \frac{2}{9}} = \frac{1}{b ^{\frac{2}{9}}}

= \frac{1}{b ^{\frac{2}{9}}}

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Frequently Asked Questions (FAQ)

What is (b^{-1/9})^2 ?
The solution to (b^{-1/9})^2 is 1/(b^{2/9)}