What are the solutions to the equation (-7)^2+(b)^2=(-25)^2 ?

The solutions to the equation (-7)^2+(b)^2=(-25)^2 are b=24,b=-24

Find the zeros of (-7)^2+(b)^2=(-25)^2

The zeros of (-7)^2+(b)^2=(-25)^2 are b=24,b=-24

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(- 7)^{2} + (b)^{2} = (- 25)^{2}

b = 24, b = - 24

Solution steps

(- 7)^{2} + b^{2} = (- 25)^{2}

Expand

(- 7)^{2} + b^{2} : 49 + b^{2}

Expand

(- 25)^{2} : 625

49 + b^{2} = 625

Move

49

to the right side

b^{2} = 576

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 576, b = - 576

576 = 24

- 576 = - 24

b = 24, b = - 24

2 \times 2

(5 + 7) (5 - 7)

6 x + 7 = 8 x - 15

2 g^{2} - 13 g + 6 = 0

0 - \frac{1}{3}

What are the solutions to the equation (-7)^2+(b)^2=(-25)^2 ?
The solutions to the equation (-7)^2+(b)^2=(-25)^2 are b=24,b=-24
Find the zeros of (-7)^2+(b)^2=(-25)^2
The zeros of (-7)^2+(b)^2=(-25)^2 are b=24,b=-24