What are the solutions to the equation 3x^2+24x+53=0 ?

The solutions to the equation 3x^2+24x+53=0 are x=-4+isqrt(5/3),x=-4-isqrt(5/3)

Find the zeros of 3x^2+24x+53=0

The zeros of 3x^2+24x+53=0 are x=-4+isqrt(5/3),x=-4-isqrt(5/3)

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3 x^{2} + 24 x + 53 = 0

x = - 4 + i \frac{5}{3}, x = - 4 - i \frac{5}{3}

Solution steps

3 x^{2} + 24 x + 53 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 3 \cdot 53}{2 \cdot 3}

Simplify

2 4^{2} - 4 \cdot 3 \cdot 53 : 215 i

x_{1, 2} = \frac{- 24 \pm 2 15 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 24 + 2 15 i}{2 \cdot 3}, x_{2} = \frac{- 24 - 2 15 i}{2 \cdot 3}

x = \frac{- 24 + 2 15 i}{2 \cdot 3} : - 4 + i \frac{5}{3}

x = \frac{- 24 - 2 15 i}{2 \cdot 3} : - 4 - i \frac{5}{3}

The solutions to the quadratic equation are:

x = - 4 + i \frac{5}{3}, x = - 4 - i \frac{5}{3}

∣ 6 - x ∣ \geq x

7 x^{2} - 43 x - 42

- (- 6)^{3}

a^{5} + a^{3} + 1000 a^{2} + 1000

8 + 6

What are the solutions to the equation 3x^2+24x+53=0 ?
The solutions to the equation 3x^2+24x+53=0 are x=-4+isqrt(5/3),x=-4-isqrt(5/3)
Find the zeros of 3x^2+24x+53=0
The zeros of 3x^2+24x+53=0 are x=-4+isqrt(5/3),x=-4-isqrt(5/3)